popikachu SG TS means x^(-1/pi)=0 answer, (1/x)^(1/pi) = 0 1/( pi root(x) ) = 0 x = 0 which means x must be zero...
ctstalin SG i tink TS meant x^-(1/pi) = 0 dam...i totally forgotten wat to do...NS has made me stupid
manyu882 SG (x^-1)/pi=0 therefore, we can say that x^-1=0 which means 1/x=0 there for, x= infniti when x approaches to 0 scenario 2 x^(-1/pi)=0 root (-1/pi) both sides. therefore x=0.
798 SG x^-(1/pi) = 0 ln (x^-(1/pi)) = ln 0 (-1/pi)ln(x)=1 ln x = -pi x = exp^-pi) forget some of the natural log rules, hopefully i'm correct.
